# The sci.math.faq on the *Monty Hall Problem*

### From version 7.5, dated: 2-20-98

*(Note: This is an excerpt from the "frequently asked questions"
-- the "FAQ" -- of the venerable USENET newsgroup "sci.math". The MHP is
discussed there not infrequently.)*

## The Monty Hall problem

*This problem has rapidly become part of the mathematical
folklore.*
*The American Mathematical Monthly, in its issue of January 1992,
explains this problem carefully. The following are excerpted from that
article.*

**Problem**

A TV host shows you three numbered doors (all three equally likely),
one hiding a car and the other two hiding goats. You get to pick a
door, winning whatever is behind it. Regardless of the door you
choose, the host, who knows where the car is, then opens one of the
other two doors to reveal a goat, and invites you to switch your
choice if you so wish. Does switching increases your chances of
winning the car?

If the host always opens one of the two other doors, you should
switch. Notice that 1/3 of the time you choose the right door (i.e.
the one with the car) and switching is wrong, while 2/3 of the time
you choose the wrong door and switching gets you the car.
Thus the expected return of switching is 2/3 which improves over your
original expected gain of 1/3.

Even if the hosts offers you to switch only part of the time, it pays
to switch. Only in the case where we assume a malicious host (i.e. a
host who entices you to switch based in the knowledge that you have
the right door) would it pay not to switch.

There are several ways to convince yourself about why it pays to
switch. Here's one. You select a door. At this time assume the host
asks you if you want to switch before he opens any doors. Even though
the odds that the door you selected is empty are high (2/3), there is
no advantage on switching as there are two doors, and you don't know
thich one to switch to. This means the 2/3 are evenly distributed,
which as good as you are doing already. However, once Monty opens one
of the two doors you selected, the chances that you selected the right
door are still 1/3 and now you only have one door to choose from if
you switch. So it pays to switch.

**References**

L. Gillman *The Car and the Goats* **American Mathematical
Monthly**, January 1992, pp. 3-7.